What is the domain of (3(x^2-2)^{1/2})/(1-x) ?

The domain of (3(x^2-2)^{1/2})/(1-x) is x = 2^{1/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (3(x^2-2)^{1/2})/(1-x)

domain

\frac{3 ( x ^{2} - 2 ) ^{\frac{1}{2}}}{1 - x}

x \leq - 2^{\frac{1}{2}} or x \geq 2^{\frac{1}{2}}

Interval Notation

(- \infty, - 2^{\frac{1}{2}}] \cup [2^{\frac{1}{2}}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2^{\frac{1}{2}} or x \geq 2^{\frac{1}{2}}

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq - 2^{\frac{1}{2}} or x \geq 2^{\frac{1}{2}}

\frac{1}{2 x + 7}, - 3 \leq x \leq 6

f (x) = x^{2} + y^{2} = 9

f (x) = 2 π r^{2} + 8 π r

f (x) = \frac{3}{( x ^{2} - x )}

f (x) = \frac{4 x + 3}{x ^{2} - 1}

What is the domain of (3(x^2-2)^{1/2})/(1-x) ?
The domain of (3(x^2-2)^{1/2})/(1-x) is x<=-2^{1/2}\lor x>= 2^{1/2}