What is the domain of f(x)=ln(9x^2-64) ?

The domain of f(x)=ln(9x^2-64) is x 8/3

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domain of f(x)=ln(9x^2-64)

domain

f (x) = ln (9 x^{2} - 64)

x < - \frac{8}{3} or x > \frac{8}{3}

Interval Notation

(- \infty, - \frac{8}{3}) \cup (\frac{8}{3}, \infty)

Solution steps

Find positive values for logs:

x < - \frac{8}{3} or x > \frac{8}{3}

The function domain

x < - \frac{8}{3} or x > \frac{8}{3}

f (x) = (x^{2} + 1)

f (x) = \frac{1}{2 x - x ^{2}}

\frac{3 - x}{x ^{2} - 4}

f (x) = arccos (\frac{x + 1}{2})

x^{3} + (4 x^{2} + 17 x - 15)

What is the domain of f(x)=ln(9x^2-64) ?
The domain of f(x)=ln(9x^2-64) is x<-8/3 \lor x> 8/3