What is the domain of f(x)=(x^2+x-2)/(x^2+3x+2) ?

The domain of f(x)=(x^2+x-2)/(x^2+3x+2) is x -1

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domain of f(x)=(x^2+x-2)/(x^2+3x+2)

domain

f (x) = \frac{x ^{2} + x - 2}{x ^{2} + 3 x + 2}

x < - 2 or - 2 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 2

The function domain

x < - 2 or - 2 < x < - 1 or x > - 1

\frac{x - 2 + ∣ x - 1 ∣}{∣ x - 2 ∣ + x - 1}

f (x) = cos (arccos (x))

f (x) = \frac{8}{( x - 4 ) ^{2}}

1 - \frac{2}{x}

f (x) = \frac{2 x ^{2} - 3 x}{x ^{2} - x - 12}

What is the domain of f(x)=(x^2+x-2)/(x^2+3x+2) ?
The domain of f(x)=(x^2+x-2)/(x^2+3x+2) is x<-2\lor-2<x<-1\lor x>-1