What is the domain of f(x)= x/(\sqrt[3]{x^3+8)} ?

The domain of f(x)= x/(\sqrt[3]{x^3+8)} is x -2

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domain of f(x)= x/(\sqrt[3]{x^3+8)}

domain

x < - 2 or x > - 2

Interval Notation

(- \infty, - 2) \cup (- 2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2

The function domain

x < - 2 or x > - 2

- \frac{15}{8}

f (x) = \frac{\frac{1}{x}}{x ^{2} - 9}

f (x) = - 4 x + 4

e^{x} + e^{- x}

\frac{x ^{2} + 15}{3}

What is the domain of f(x)= x/(\sqrt[3]{x^3+8)} ?
The domain of f(x)= x/(\sqrt[3]{x^3+8)} is x<-2\lor x>-2