What is the domain of f(x)=(x+1)ln^2(x+1) ?

The domain of f(x)=(x+1)ln^2(x+1) is x>-1

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domain of f(x)=(x+1)ln^2(x+1)

domain

f (x) = (x + 1) ln^{2} (x + 1)

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find positive values for logs:

x > - 1

The function domain

x > - 1

f (x) = x^{3} - 3 x^{2} + 7 x + 1

f (x) = \frac{x}{3}

f (x) = \frac{x ^{3} + x ^{2} + x + 1}{∣ x + 1 ∣}

x^{3} - 3 x^{2} + 1

f (x) = \frac{3 x}{x + 1}

What is the domain of f(x)=(x+1)ln^2(x+1) ?
The domain of f(x)=(x+1)ln^2(x+1) is x>-1