What is the domain of f(x)=(sqrt(2x+3))/(sqrt(x-9)) ?

The domain of f(x)=(sqrt(2x+3))/(sqrt(x-9)) is x>9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sqrt(2x+3))/(sqrt(x-9))

domain

f (x) = \frac{2 x + 3}{x - 9}

x > 9

Interval Notation

(9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x > 9

\frac{x ^{2} - 1}{4 - x ^{2}}

- 4 2 x - 8

f (x) = \frac{x}{ln ( 1 - x )}

f (x) = \frac{1 - x ^{2} + x}{∣ x - 2 ∣ + 2}

f (x) = 5 x - 4

What is the domain of f(x)=(sqrt(2x+3))/(sqrt(x-9)) ?
The domain of f(x)=(sqrt(2x+3))/(sqrt(x-9)) is x>9