What is the domain of f(x)=(sqrt(1-x^2)+x)/(|x-2|+2) ?

The domain of f(x)=(sqrt(1-x^2)+x)/(|x-2|+2) is -1<= x<= 1

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domain of f(x)=(sqrt(1-x^2)+x)/(|x-2|+2)

domain

f (x) = \frac{1 - x ^{2} + x}{∣ x - 2 ∣ + 2}

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

No real undefined points

Combine real regions and undefined points for final function domain

- 1 \leq x \leq 1

f (x) = 5 x - 4

f (x) = lo g_{10} (6 x^{2} - 13 x - 28)

f (x) = \frac{8 x ^{2} + 12 x}{9 x ^{2} - 12 x + 4}

g (t) = 2 t - 1

e^{- x} + 2

What is the domain of f(x)=(sqrt(1-x^2)+x)/(|x-2|+2) ?
The domain of f(x)=(sqrt(1-x^2)+x)/(|x-2|+2) is -1<= x<= 1