What is the domain of f(x)=log_{10}(6x^2-13x-28) ?

The domain of f(x)=log_{10}(6x^2-13x-28) is x 7/2

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domain of f(x)=log_{10}(6x^2-13x-28)

domain

f (x) = lo g_{10} (6 x^{2} - 13 x - 28)

x < - \frac{4}{3} or x > \frac{7}{2}

Interval Notation

(- \infty, - \frac{4}{3}) \cup (\frac{7}{2}, \infty)

Solution steps

Find positive values for logs:

x < - \frac{4}{3} or x > \frac{7}{2}

The function domain

x < - \frac{4}{3} or x > \frac{7}{2}

f (x) = \frac{8 x ^{2} + 12 x}{9 x ^{2} - 12 x + 4}

g (t) = 2 t - 1

e^{- x} + 2

e^{- x} + 3

f (x) = \frac{( x 5 ^{x} )}{5 ^{(x + 2)} - 1}

What is the domain of f(x)=log_{10}(6x^2-13x-28) ?
The domain of f(x)=log_{10}(6x^2-13x-28) is x<-4/3 \lor x> 7/2