What is the domain of f(x)=\sqrt[3]{y/(y-3)} ?

The domain of f(x)=\sqrt[3]{y/(y-3)} is y 3

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domain of f(x)=\sqrt[3]{y/(y-3)}

domain

y < 3 or y > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

y = 3

The function domain

y < 3 or y > 3

f (x) = \frac{1}{4 x + 7}

f (t) = 16 - t^{2}

3 x + 1

(x + 1) ln^{2} (x + 1)

\frac{x ^{3} + 3 x ^{2} + 1}{4 x ( x - 1 ) ^{2}}

What is the domain of f(x)=\sqrt[3]{y/(y-3)} ?
The domain of f(x)=\sqrt[3]{y/(y-3)} is y<3\lor y>3