What is the domain of f(x)=(2-x)/(sqrt(x^4-1)) ?

The domain of f(x)=(2-x)/(sqrt(x^4-1)) is x 1

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domain of f(x)=(2-x)/(sqrt(x^4-1))

domain

f (x) = \frac{2 - x}{x ^{4} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = 4 - x^{2} - 4 x

\frac{( 4 x ^{2} + 17 x - 15 )}{( x ^{3} )}

x^{2} = y - 1

f (x) = \frac{x ^{3}}{1 - x}

f (x) = \frac{1}{4 x - 3}

What is the domain of f(x)=(2-x)/(sqrt(x^4-1)) ?
The domain of f(x)=(2-x)/(sqrt(x^4-1)) is x<-1\lor x>1