What is the domain of y=(x^2+x-12)/(x^2-4) ?

The domain of y=(x^2+x-12)/(x^2-4) is x 2

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domain of y=(x^2+x-12)/(x^2-4)

domain

y = \frac{x ^{2} + x - 12}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

h (x) = \frac{x + 5}{x ^{2} - 9}

y = 4 + \frac{5}{1 + x - 3}

y = \frac{2}{x + 3}

f (x) = 5 (x^{2} - 20)

∣ x - 4 ∣

What is the domain of y=(x^2+x-12)/(x^2-4) ?
The domain of y=(x^2+x-12)/(x^2-4) is x<-2\lor-2<x<2\lor x>2