What is the domain of 2/(\frac{5){x-1}+3} ?

The domain of 2/(\frac{5){x-1}+3} is x 1

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domain of 2/(\frac{5){x-1}+3}

domain

\frac{2}{\frac{5}{x - 1} + 3}

x < - \frac{2}{3} or - \frac{2}{3} < x < 1 or x > 1

Interval Notation

(- \infty, - \frac{2}{3}) \cup (- \frac{2}{3}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{2}{3}, x = 1

The function domain

x < - \frac{2}{3} or - \frac{2}{3} < x < 1 or x > 1

f (x) = \frac{2 x ^{2} + x - 6}{x + 2}

U (d) = - 0.33 d^{2} + 7 d + 30

f (x) = \frac{1}{tan ^{2} ( x ) - 3}

y = x^{2} (x + 1)^{3} (x - 3)

\frac{1 - 9 4 - x ^{2}}{∣ x - 2 ∣ - ∣ x + 2 ∣}

What is the domain of 2/(\frac{5){x-1}+3} ?
The domain of 2/(\frac{5){x-1}+3} is x<-2/3 \lor-2/3 <x<1\lor x>1