What is the domain of f(x)= 1/(sqrt(-x^2+x)) ?

The domain of f(x)= 1/(sqrt(-x^2+x)) is 0<x<1

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domain of f(x)= 1/(sqrt(-x^2+x))

domain

f (x) = \frac{1}{- x ^{2} + x}

0 < x < 1

Interval Notation

(0, 1)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 1

Find undefined (singularity) points:

x = 0, x = 1

Combine real regions and undefined points for final function domain

0 < x < 1

f (x) = - 8 x + 40

f (x) = 3 - 2 x + 1 - x

- 2 x + 4

\frac{1}{x - 2} x + 4

f (x) = \frac{3}{x ^{2} - 4 x - 12}

What is the domain of f(x)= 1/(sqrt(-x^2+x)) ?
The domain of f(x)= 1/(sqrt(-x^2+x)) is 0<x<1