What is the domain of f(x)=3-(x+1)^2,-3<x<= 1 ?

The domain of f(x)=3-(x+1)^2,-3<x<= 1 is -3<x<= 1

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domain of f(x)=3-(x+1)^2,-3<x<= 1

domain

f (x) = 3 - (x + 1)^{2}, - 3 < x \leq 1

- 3 < x \leq 1

Interval Notation

(- 3, 1]

Solution steps

Set the domain to the given interval

- 3 < x \leq 1

The function has no undefined points nor domain constraints. Therefore, the domain is

- 3 < x \leq 1

x (\frac{4 x + 1976}{x - 6})

f (x) = (x - 1) (x - 6)

f (x) = 2 x^{2} + 8 x + 3

f (x) = x^{4} - 3 x^{3} - x^{2} + 5 x - 1

g (x) = x^{2} - 4

What is the domain of f(x)=3-(x+1)^2,-3<x<= 1 ?
The domain of f(x)=3-(x+1)^2,-3<x<= 1 is -3<x<= 1