What is the domain of f(x)=sqrt(-x^2+8x) ?

The domain of f(x)=sqrt(-x^2+8x) is 0<= x<= 8

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domain of f(x)=sqrt(-x^2+8x)

domain

f (x) = - x^{2} + 8 x

0 \leq x \leq 8

Interval Notation

[0, 8]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 8

The function domain

0 \leq x \leq 8

f (x) = \frac{x ^{2} + 2}{x - 2}

f (x) = 4 x^{3} - 5 x - 1

1.5 (2)^{x}

f (x) = arccos (\frac{x ^{2} - x - 13}{7})

f (x) = ln (2 - x - x^{2})

What is the domain of f(x)=sqrt(-x^2+8x) ?
The domain of f(x)=sqrt(-x^2+8x) is 0<= x<= 8