What is the domain of f(x)=sqrt((x+1)/x) ?

The domain of f(x)=sqrt((x+1)/x) is x 0

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domain of f(x)=sqrt((x+1)/x)

domain

f (x) = \frac{x + 1}{x}

x \leq - 1 or x > 0

Interval Notation

(- \infty, - 1] \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x > 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 1 or x > 0

f (x) = - (3 x)^{\frac{1}{2}} - 4

y = 2 x - 9

\frac{x}{x ^{2} - 2 x}

y = \frac{2 x - 3}{x + 2}

g (x) = ln (6 - x)

What is the domain of f(x)=sqrt((x+1)/x) ?
The domain of f(x)=sqrt((x+1)/x) is x<=-1\lor x>0