What is the domain of f(x)=-(3x)^{1/2}-4 ?

The domain of f(x)=-(3x)^{1/2}-4 is x>= 0

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domain of f(x)=-(3x)^{1/2}-4

domain

f (x) = - (3 x)^{\frac{1}{2}} - 4

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

y = 2 x - 9

\frac{x}{x ^{2} - 2 x}

y = \frac{2 x - 3}{x + 2}

g (x) = ln (6 - x)

f (x) = 2 x + 16

What is the domain of f(x)=-(3x)^{1/2}-4 ?
The domain of f(x)=-(3x)^{1/2}-4 is x>= 0