What is the domain of f(x)=sqrt(2x+16) ?

The domain of f(x)=sqrt(2x+16) is x>=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(2x+16)

domain

f (x) = 2 x + 16

x \geq - 8

Interval Notation

[- 8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

The function domain

x \geq - 8

2 x + 15

f (x) = \frac{x}{x + 3} + 5

h (x) = x + 1

f (x) = \frac{2 x - 5}{7 x + 3}

f (x) = - x^{2} + 7 x - 12

What is the domain of f(x)=sqrt(2x+16) ?
The domain of f(x)=sqrt(2x+16) is x>=-8