What is the domain of f(x)=sqrt(x/(x+3)+5) ?

The domain of f(x)=sqrt(x/(x+3)+5) is x =-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x/(x+3)+5)

domain

f (x) = \frac{x}{x + 3} + 5

x < - 3 or x \geq - \frac{5}{2}

Interval Notation

(- \infty, - 3) \cup [- \frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x < - 3 or x \geq - \frac{5}{2}

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x \geq - \frac{5}{2}

h (x) = x + 1

f (x) = \frac{2 x - 5}{7 x + 3}

f (x) = - x^{2} + 7 x - 12

\frac{- 2 x + 4}{x - 6}

x^{3}

What is the domain of f(x)=sqrt(x/(x+3)+5) ?
The domain of f(x)=sqrt(x/(x+3)+5) is x<-3\lor x>=-5/2