What is the domain of f(x)=3+sqrt(6x-3) ?

The domain of f(x)=3+sqrt(6x-3) is x>= 1/2

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domain of f(x)=3+sqrt(6x-3)

domain

f (x) = 3 + 6 x - 3

x \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

The function domain

x \geq \frac{1}{2}

\frac{( x ^{3} )}{( 4 x ^{2} + 17 x - 15 )}

f (x) = \frac{7}{3 - 6 x}

f (x) = \frac{2 x ^{3}}{x ^{2} - 4}

f (x) = x - 36

\frac{2 x - 6}{x + 3}

What is the domain of f(x)=3+sqrt(6x-3) ?
The domain of f(x)=3+sqrt(6x-3) is x>= 1/2