What is the domain of f(x)=sqrt(10-2x+3\sqrt{x-1)} ?

The domain of f(x)=sqrt(10-2x+3\sqrt{x-1)} is 1<= x<= (3sqrt(73)+49)/8

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domain of f(x)=sqrt(10-2x+3\sqrt{x-1)}

domain

f (x) = 10 - 2 x + 3 x - 1

1 \leq x \leq \frac{3 73 + 49}{8}

Interval Notation

[1, \frac{3 73 + 49}{8}]

Solution steps

Find non-negative values for radicals:

1 \leq x \leq \frac{3 73 + 49}{8}

The function domain

1 \leq x \leq \frac{3 73 + 49}{8}

f (x) = \frac{x ^{2} - 36}{x - 6}

f (x) = \frac{1}{5} x^{3} - x^{2} + 1

lo g_{e} (x^{2} - 1)

f (x) = 4 (x - 12) (x - 7)

∣ 2 x ∣ - 2

What is the domain of f(x)=sqrt(10-2x+3\sqrt{x-1)} ?
The domain of f(x)=sqrt(10-2x+3\sqrt{x-1)} is 1<= x<= (3sqrt(73)+49)/8