What is the domain of sqrt(x^2-8x+15) ?

The domain of sqrt(x^2-8x+15) is x = 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(x^2-8x+15)

domain

x^{2} - 8 x + 15

x \leq 3 or x \geq 5

Interval Notation

(- \infty, 3] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 3 or x \geq 5

The function domain

x \leq 3 or x \geq 5

f (x) = \frac{1}{x ^{2} + 3 x - 4}

f (x) = \frac{x}{1 - x}

y = arccos (3 - 2 x)

\frac{1}{- x ^{2} + 5 x}

f (x) = ln (x^{2} + 16)

What is the domain of sqrt(x^2-8x+15) ?
The domain of sqrt(x^2-8x+15) is x<= 3\lor x>= 5