What is the domain of y=sqrt(x)+sqrt(4-x) ?

The domain of y=sqrt(x)+sqrt(4-x) is 0<= x<= 4

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domain of y=sqrt(x)+sqrt(4-x)

domain

y = x + 4 - x

0 \leq x \leq 4

Interval Notation

[0, 4]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 4

The function domain

0 \leq x \leq 4

f (x) = 27 - 3 x^{2}

f (x) = \frac{2 x ^{2} + 6 x + 5}{x ^{2} + 3 x + 2}

\frac{2 x + 5}{3 x ^{2} - 10 x - 8}

f (x) = \frac{1 - x}{x ^{2} - 5 x + 4}

f (x) = \frac{4 x - 9}{x ^{2} - 4}

What is the domain of y=sqrt(x)+sqrt(4-x) ?
The domain of y=sqrt(x)+sqrt(4-x) is 0<= x<= 4