What is the domain of f(x)=(2x^2+6x+5)/(x^2+3x+2) ?

The domain of f(x)=(2x^2+6x+5)/(x^2+3x+2) is x -1

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domain of f(x)=(2x^2+6x+5)/(x^2+3x+2)

domain

f (x) = \frac{2 x ^{2} + 6 x + 5}{x ^{2} + 3 x + 2}

x < - 2 or - 2 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 2

The function domain

x < - 2 or - 2 < x < - 1 or x > - 1

\frac{2 x + 5}{3 x ^{2} - 10 x - 8}

f (x) = \frac{1 - x}{x ^{2} - 5 x + 4}

f (x) = \frac{4 x - 9}{x ^{2} - 4}

f (x) = - 2 (x + 2) (x - 3) (x - 1)

y = sin (2 x)

What is the domain of f(x)=(2x^2+6x+5)/(x^2+3x+2) ?
The domain of f(x)=(2x^2+6x+5)/(x^2+3x+2) is x<-2\lor-2<x<-1\lor x>-1