What is the domain of f(x)=(1-7x)/(sqrt(x^2-4x)) ?

The domain of f(x)=(1-7x)/(sqrt(x^2-4x)) is x 4

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domain of f(x)=(1-7x)/(sqrt(x^2-4x))

domain

f (x) = \frac{1 - 7 x}{x ^{2} - 4 x}

x < 0 or x > 4

Interval Notation

(- \infty, 0) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

Find undefined (singularity) points:

x = 4, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 4

\frac{2}{∣ x - 2 ∣ - 1}

f (x) = \frac{x - 3}{x ^{2} + 6 x - 27}

f (x) = 5 - 10 x

y = \frac{2 ^{2 - x}}{x}

\frac{1}{x - 9}

What is the domain of f(x)=(1-7x)/(sqrt(x^2-4x)) ?
The domain of f(x)=(1-7x)/(sqrt(x^2-4x)) is x<0\lor x>4