What is the domain of f(x)=(x^2-5x-6)/(x^2-3x-18) ?

The domain of f(x)=(x^2-5x-6)/(x^2-3x-18) is x 6

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domain of f(x)=(x^2-5x-6)/(x^2-3x-18)

domain

f (x) = \frac{x ^{2} - 5 x - 6}{x ^{2} - 3 x - 18}

x < - 3 or - 3 < x < 6 or x > 6

Interval Notation

(- \infty, - 3) \cup (- 3, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 3

The function domain

x < - 3 or - 3 < x < 6 or x > 6

\frac{x + 4}{- 2 x - 6}

f (x) = 2 x - 6

\frac{1}{arccos ( x )}

f (x) = \frac{5 x - 10}{x ^{2} + 5 x - 14}

f (x) = \frac{1}{x ^{2}} - 3

What is the domain of f(x)=(x^2-5x-6)/(x^2-3x-18) ?
The domain of f(x)=(x^2-5x-6)/(x^2-3x-18) is x<-3\lor-3<x<6\lor x>6