What is the domain of f(x)=(x-1)/(x^2+2x-3) ?

The domain of f(x)=(x-1)/(x^2+2x-3) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x-1)/(x^2+2x-3)

domain

f (x) = \frac{x - 1}{x ^{2} + 2 x - 3}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 3

The function domain

x < - 3 or - 3 < x < 1 or x > 1

y = \frac{x}{x + 2} - \frac{x}{x - 2}

x^{2} - 6 x - 3

f (x) = \frac{10}{x ^{2} + 1}

f (x) = \frac{x}{x ^{2} + x - 2}

x^{\frac{1}{5}} (x - 4)

What is the domain of f(x)=(x-1)/(x^2+2x-3) ?
The domain of f(x)=(x-1)/(x^2+2x-3) is x<-3\lor-3<x<1\lor x>1