What is the domain of (sqrt(x)-1)^2 ?

The domain of (sqrt(x)-1)^2 is x>= 0

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domain of (sqrt(x)-1)^2

domain

(x - 1)^{2}

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (r) = \frac{2}{r ^{2} + 1}

f (x) = \frac{2 x + 1}{5 - x}

y = \frac{4 x + 3}{2 x - 1}

cos (\frac{1}{x})

f (x) = \frac{x + 1}{2 - x}