What is the domain of sqrt(4+ln(x)) ?

The domain of sqrt(4+ln(x)) is x>= 1/(e^4)

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domain of sqrt(4+ln(x))

domain

4 + ln (x)

x \geq \frac{1}{e ^{4}}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{4}}

The function domain

x \geq \frac{1}{e ^{4}}

lo g_{\frac{1}{3}} (\frac{x ^{2} - x - 6}{2}) + x + 1

f (x) = x + 9

f (x) = \frac{2 x ^{2}}{x ^{2} - 6 x - 7}

f (x) = (ln (x))

3 x^{3} - 6 x^{2} + 15 x + 21

What is the domain of sqrt(4+ln(x)) ?
The domain of sqrt(4+ln(x)) is x>= 1/(e^4)