What is the domain of (sqrt(x^2-4))/(sqrt(x^2-9)) ?

The domain of (sqrt(x^2-4))/(sqrt(x^2-9)) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (sqrt(x^2-4))/(sqrt(x^2-9))

domain

\frac{x ^{2} - 4}{x ^{2} - 9}

x < - 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x > 3

g (z) = - z^{2} - 4 z + 7

\frac{x}{x + 10} + x^{2} + 6 x - 7

f (x) = (\frac{x}{4 - x ^{2}})

2 x - 5

\frac{x - 6}{x - 4}

What is the domain of (sqrt(x^2-4))/(sqrt(x^2-9)) ?
The domain of (sqrt(x^2-4))/(sqrt(x^2-9)) is x<-3\lor x>3