What is the domain of f(x)=(x/(sqrt(4-x^2))) ?

The domain of f(x)=(x/(sqrt(4-x^2))) is -2<x<2

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domain of f(x)=(x/(sqrt(4-x^2)))

domain

f (x) = (\frac{x}{4 - x ^{2}})

- 2 < x < 2

Interval Notation

(- 2, 2)

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

- 2 < x < 2

2 x - 5

\frac{x - 6}{x - 4}

f (x) = \frac{5}{9}

\frac{7 x}{x - 5}

f (t) = \frac{1}{ln ( t )}

What is the domain of f(x)=(x/(sqrt(4-x^2))) ?
The domain of f(x)=(x/(sqrt(4-x^2))) is -2<x<2