What is the domain of f(t)= 1/(ln(t)) ?

The domain of f(t)= 1/(ln(t)) is 0 1

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domain of f(t)= 1/(ln(t))

domain

f (t) = \frac{1}{ln ( t )}

0 < t < 1 or t > 1

Interval Notation

(0, 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

t > 0

Find undefined (singularity) points:

t = 1

Combine real regions and undefined points for final function domain

0 < t < 1 or t > 1

f (x) = \frac{8 x ^{2} + 12 x}{( 3 x - 2 ) ^{2}}

f (x) = [2 (x + 3)]^{2} + 3

f (x) = \frac{9 - x ^{2}}{x + 1}

f (x) = (- 2.2)

f (x) = \frac{2}{x ^{3} + 27}

What is the domain of f(t)= 1/(ln(t)) ?
The domain of f(t)= 1/(ln(t)) is 0<t<1\lor t>1