What is the domain of f(x)=(8x^2+12x)/((3x-2)^2) ?

The domain of f(x)=(8x^2+12x)/((3x-2)^2) is x 2/3

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domain of f(x)=(8x^2+12x)/((3x-2)^2)

domain

f (x) = \frac{8 x ^{2} + 12 x}{( 3 x - 2 ) ^{2}}

x < \frac{2}{3} or x > \frac{2}{3}

Interval Notation

(- \infty, \frac{2}{3}) \cup (\frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{3}

The function domain

x < \frac{2}{3} or x > \frac{2}{3}

f (x) = [2 (x + 3)]^{2} + 3

f (x) = \frac{9 - x ^{2}}{x + 1}

f (x) = (- 2.2)

f (x) = \frac{2}{x ^{3} + 27}

x - \frac{2 x - \frac{3}{3 x} - 2}{3 x} 4

What is the domain of f(x)=(8x^2+12x)/((3x-2)^2) ?
The domain of f(x)=(8x^2+12x)/((3x-2)^2) is x< 2/3 \lor x> 2/3