What is the domain of f(x)= 2/(sqrt(x^3+27)) ?

The domain of f(x)= 2/(sqrt(x^3+27)) is x>-3

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domain of f(x)= 2/(sqrt(x^3+27))

domain

f (x) = \frac{2}{x ^{3} + 27}

x > - 3

Interval Notation

(- 3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x > - 3

x - \frac{2 x - \frac{3}{3 x} - 2}{3 x} 4

y = x - \frac{4}{x}

f (x) = \frac{x}{x ^{2} + 16}

\frac{2 x ^{2} + 3 x - 5}{x ^{2} + 2}

h (x) = 3 3 x + 1

What is the domain of f(x)= 2/(sqrt(x^3+27)) ?
The domain of f(x)= 2/(sqrt(x^3+27)) is x>-3