What is the domain of f(x)=sqrt(x/(x^2+16)) ?

The domain of f(x)=sqrt(x/(x^2+16)) is x>= 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x/(x^2+16))

domain

f (x) = \frac{x}{x ^{2} + 16}

x \geq 0

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

\frac{2 x ^{2} + 3 x - 5}{x ^{2} + 2}

h (x) = 3 3 x + 1

f (x) = 3 x^{- 2}

g (x) = 3^{x} + 3

∣ x + 2 ∣

What is the domain of f(x)=sqrt(x/(x^2+16)) ?
The domain of f(x)=sqrt(x/(x^2+16)) is x>= 0