What is the domain of f(x)=(sqrt(9-x^2))/(x-2) ?

The domain of f(x)=(sqrt(9-x^2))/(x-2) is -3<= x<2\lor 2<x<= 3

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domain of f(x)=(sqrt(9-x^2))/(x-2)

domain

f (x) = \frac{9 - x ^{2}}{x - 2}

- 3 \leq x < 2 or 2 < x \leq 3

Interval Notation

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 3 \leq x < 2 or 2 < x \leq 3

f (x) = 5^{x + 1}

3 x - x^{2} + \frac{28}{x - 10} + 5 x

x + 17

\frac{x}{x - 8}

g (x) = x^{2} - 3 x

What is the domain of f(x)=(sqrt(9-x^2))/(x-2) ?
The domain of f(x)=(sqrt(9-x^2))/(x-2) is -3<= x<2\lor 2<x<= 3