What is the domain of-1/2 (x+4)^2+8 ?

The domain of-1/2 (x+4)^2+8 is -infinity <x<infinity

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domain of-1/2 (x+4)^2+8

domain

- \frac{1}{2} (x + 4)^{2} + 8

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (t) = t - 2

f (x) = \frac{5 x - 7}{4}

f (x) = \frac{9 x - 5}{x ^{2} + 7 x + 12}

\frac{x ^{2} - 9}{x ^{2} - 2 x - 8}

\frac{1}{lo g _{10} ( x ^{2} - 4 )}

What is the domain of-1/2 (x+4)^2+8 ?
The domain of-1/2 (x+4)^2+8 is -infinity <x<infinity