What is the domain of f(x)=(9x-5)/(x^2+7x+12) ?

The domain of f(x)=(9x-5)/(x^2+7x+12) is x -3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(9x-5)/(x^2+7x+12)

domain

f (x) = \frac{9 x - 5}{x ^{2} + 7 x + 12}

x < - 4 or - 4 < x < - 3 or x > - 3

Interval Notation

(- \infty, - 4) \cup (- 4, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3, x = - 4

The function domain

x < - 4 or - 4 < x < - 3 or x > - 3

\frac{x ^{2} - 9}{x ^{2} - 2 x - 8}

\frac{1}{lo g _{10} ( x ^{2} - 4 )}

f (x) = 3 x - 10

\frac{9 - x ^{2}}{x}

y = arccos (\frac{- x + 2}{2}) + \frac{π}{2}

What is the domain of f(x)=(9x-5)/(x^2+7x+12) ?
The domain of f(x)=(9x-5)/(x^2+7x+12) is x<-4\lor-4<x<-3\lor x>-3