What is the domain of y= 4/(\frac{2){x-1}+3} ?

The domain of y= 4/(\frac{2){x-1}+3} is x 1

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domain of y= 4/(\frac{2){x-1}+3}

domain

y = \frac{4}{\frac{2}{x - 1} + 3}

x < \frac{1}{3} or \frac{1}{3} < x < 1 or x > 1

Interval Notation

(- \infty, \frac{1}{3}) \cup (\frac{1}{3}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{3}, x = 1

The function domain

x < \frac{1}{3} or \frac{1}{3} < x < 1 or x > 1

\frac{3 x + 1}{5}

f (x) = x^{3} + 3 x^{2}

f (x) = x - 3 + 1

f (x) = \frac{2 x + 1}{x ^{2} + 1}

f (x) = \frac{( x + 9 )}{x ^{2} - 81}

What is the domain of y= 4/(\frac{2){x-1}+3} ?
The domain of y= 4/(\frac{2){x-1}+3} is x< 1/3 \lor 1/3 <x<1\lor x>1