What is the domain of f(x)=sqrt(x-3)+1 ?

The domain of f(x)=sqrt(x-3)+1 is x>= 3

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domain of f(x)=sqrt(x-3)+1

domain

f (x) = x - 3 + 1

x \geq 3

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

f (x) = \frac{2 x + 1}{x ^{2} + 1}

f (x) = \frac{( x + 9 )}{x ^{2} - 81}

f (x) = - 5 x^{2} + 5

f (x) = 1 - \frac{1}{x ^{2}}

y = 0.3 (x - 4)^{2} - 7.5

What is the domain of f(x)=sqrt(x-3)+1 ?
The domain of f(x)=sqrt(x-3)+1 is x>= 3