What is the domain of f(x)=sqrt(1-2x)-sqrt(3-2x-x^2) ?

The domain of f(x)=sqrt(1-2x)-sqrt(3-2x-x^2) is -3<= x<= 1/2

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domain of f(x)=sqrt(1-2x)-sqrt(3-2x-x^2)

domain

f (x) = 1 - 2 x - 3 - 2 x - x^{2}

- 3 \leq x \leq \frac{1}{2}

Interval Notation

[- 3, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq \frac{1}{2}

The function domain

- 3 \leq x \leq \frac{1}{2}

f (x) = 175 x^{2} - x

\frac{2 x}{x ^{2} + 3 x}

y^{3} = x

f (x) = \frac{x + 1}{x ^{2} + x - 2}

f (x) = 4 x^{2} + 4 x - 2

What is the domain of f(x)=sqrt(1-2x)-sqrt(3-2x-x^2) ?
The domain of f(x)=sqrt(1-2x)-sqrt(3-2x-x^2) is -3<= x<= 1/2