What is the domain of f(x)=(2x+1)/(x^2+x-56) ?

The domain of f(x)=(2x+1)/(x^2+x-56) is x 7

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domain of f(x)=(2x+1)/(x^2+x-56)

domain

f (x) = \frac{2 x + 1}{x ^{2} + x - 56}

x < - 8 or - 8 < x < 7 or x > 7

Interval Notation

(- \infty, - 8) \cup (- 8, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 8

The function domain

x < - 8 or - 8 < x < 7 or x > 7

f (x) = \frac{5 - x}{lo g _{10} ( x )}

f (x) = \frac{1}{7}

\frac{x ^{2} - 4 x + 3}{x + 1}

f (x) = x + 3 + 1

f (x) = - 6 x 5 2 x + 6

What is the domain of f(x)=(2x+1)/(x^2+x-56) ?
The domain of f(x)=(2x+1)/(x^2+x-56) is x<-8\lor-8<x<7\lor x>7