What is the domain of sqrt(3-2x)+1 ?

The domain of sqrt(3-2x)+1 is x<= 3/2

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domain of sqrt(3-2x)+1

domain

3 - 2 x + 1

x \leq \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{3}{2}

The function domain

x \leq \frac{3}{2}

f (x) = 4 - 24 - 2 x - x^{2}

2 - 4 x

f (x) = \frac{x + 2}{x ^{2} + 4}

f (x) = \frac{1}{2 x + 7}

\frac{x - 4}{x ^{2} - 2 x - 15}