What is the domain of f(x)= 1/(2x+7) ?

The domain of f(x)= 1/(2x+7) is x -7/2

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domain of f(x)= 1/(2x+7)

domain

f (x) = \frac{1}{2 x + 7}

x < - \frac{7}{2} or x > - \frac{7}{2}

Interval Notation

(- \infty, - \frac{7}{2}) \cup (- \frac{7}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{7}{2}

The function domain

x < - \frac{7}{2} or x > - \frac{7}{2}

\frac{x - 4}{x ^{2} - 2 x - 15}

f (x) = \frac{x - 4}{x}

g (x) = \frac{1}{x} - \frac{3}{x + 2}

f (x) = - 3^{- x}

f (x) = x^{2} + \frac{16}{x}

What is the domain of f(x)= 1/(2x+7) ?
The domain of f(x)= 1/(2x+7) is x<-7/2 \lor x>-7/2