What is the domain of g(x)= 1/x-3/(x+2) ?

The domain of g(x)= 1/x-3/(x+2) is x 0

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domain of g(x)= 1/x-3/(x+2)

domain

g (x) = \frac{1}{x} - \frac{3}{x + 2}

x < - 2 or - 2 < x < 0 or x > 0

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2

The function domain

x < - 2 or - 2 < x < 0 or x > 0

f (x) = - 3^{- x}

f (x) = x^{2} + \frac{16}{x}

\frac{5 x + 25}{9}

f (r) = 3.14 r^{2}

\frac{8}{3 - x}

What is the domain of g(x)= 1/x-3/(x+2) ?
The domain of g(x)= 1/x-3/(x+2) is x<-2\lor-2<x<0\lor x>0