What is the domain of (x^2-4x-8)/([-3.6]) ?

The domain of (x^2-4x-8)/([-3.6]) is -infinity <x<infinity

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domain of (x^2-4x-8)/([-3.6])

domain

\frac{x ^{2} - 4 x - 8}{[ - 3.6 ]}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{- 8 x + 9}{1 + x}

f (x) = arcsin (\frac{x - 3}{2})

y = 21 x + 9 x^{2} - x^{3}

f (x) = lo g_{10} (- (x - 5)) + 4

f (x) = - 1 + lo g_{2} (x - 5)

What is the domain of (x^2-4x-8)/([-3.6]) ?
The domain of (x^2-4x-8)/([-3.6]) is -infinity <x<infinity