What is the domain of (x^2-x+9)/(x-1) ?

The domain of (x^2-x+9)/(x-1) is x 1

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domain of (x^2-x+9)/(x-1)

domain

\frac{x ^{2} - x + 9}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

y = \frac{8 x ^{2} + 12 x}{3 x - 2}

y = \frac{7 x + 2}{2 x + 9}

f (x) = 1 - 2 x - 3

- x^{2} + 6 x - 7

f (x) = \frac{1}{- x ^{2} + 8 x}

What is the domain of (x^2-x+9)/(x-1) ?
The domain of (x^2-x+9)/(x-1) is x<1\lor x>1