What is the domain of f(x)= 1/(sqrt(-x^2+8x)) ?

The domain of f(x)= 1/(sqrt(-x^2+8x)) is 0<x<8

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domain of f(x)= 1/(sqrt(-x^2+8x))

domain

f (x) = \frac{1}{- x ^{2} + 8 x}

0 < x < 8

Interval Notation

(0, 8)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 8

Find undefined (singularity) points:

x = 0, x = 8

Combine real regions and undefined points for final function domain

0 < x < 8

lo g_{5} (x + 2)

y = arccos (\frac{- x}{2}) + \frac{π}{2}

g (x) = - lo g_{4} (x)

\frac{3 x + 4}{x ^{2} - 9}

What is the domain of f(x)= 1/(sqrt(-x^2+8x)) ?
The domain of f(x)= 1/(sqrt(-x^2+8x)) is 0<x<8