What is the domain of (3x+4)/(x^2-9) ?

The domain of (3x+4)/(x^2-9) is x 3

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domain of (3x+4)/(x^2-9)

domain

\frac{3 x + 4}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = 2 - ∣ x - 1 ∣

- 8 x + 16

f (x) = \frac{9 + x}{e ^{c o s (x)}}

g (t) = 4 t^{2} - t + 1

y = x^{3} - x^{2} + x

What is the domain of (3x+4)/(x^2-9) ?
The domain of (3x+4)/(x^2-9) is x<-3\lor-3<x<3\lor x>3