What is the domain of g(t)=4t^2-t+1 ?

The domain of g(t)=4t^2-t+1 is -infinity <t<infinity

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domain of g(t)=4t^2-t+1

domain

g (t) = 4 t^{2} - t + 1

- \infty < t < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < t < \infty

y = x^{3} - x^{2} + x

f (x) = \frac{2 x - 3}{x - 2}

\frac{( 2 x )}{x ^{2} - 1}

f (x) = \frac{3 x + 1}{5}

f (x) = 2 x^{2} + 8 x - 1

What is the domain of g(t)=4t^2-t+1 ?
The domain of g(t)=4t^2-t+1 is -infinity <t<infinity